Today, I shall use the theorem of Michael discussed earlier to prove that a metric space is paracompact.
Theorem 1 (Stone) A metric space is paracompact.
This theorem seems to use the axiom of choice, or some version thereof, in all proofs.
1. Proof of Stone’s theorem
Suppose given a cover of the metric space
(with metric
, say). We will show that there is a refinement of
that can be decomposed into a countable collection of locally finite families. Thanks to Michael’s theorem, this will prove the result.
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