I am now aiming to prove an important fixed point theorem:
Theorem 1 (Elie Cartan) Let
be a compact Lie group acting by isometries on a simply connected, complete Riemannian manifold
of negative curvature. Then there is a common fixed point of all
.
There are several ingredients in the proof of this result. These will provide examples of the techniques that I have discussed in past posts.
Geodesic triangles
Let be a manifold of negative curvature, and let
be a normal neighborhood of
; this means that
is a diffeomorphism of some neighborhood of
onto
, and any two points in
are connected by a unique geodesic. (This always exists by the normal neighborhood theorem, which I never proved. However, in the case of Cartan’s fixed point theorem, we can take
by Cartan-Hadamard.)
So take . Draw the geodesics
between the respective pairs of points, and let
be the inverse images in
under
. Note that
are straight lines, but
is not in general. Let
be the points in
corresponding to
respectively. Let
be the angle between
; it is equivalently the angle at the origin between the lines
, which is measured through the inner product structure.
Now from the figure and since geodesics travel at unit speed, and similarly for
. Moreover, we have
, where the first inequality comes from the fact that
has negative curvature and
then increases the lengths of curves; this was established in the proof of the Cartan-Hadamard theorem.
We have evidently by the left-hand-side of the figure
In particular, all this yields
So we have a cosine inequality.
There is in fact an ordinary plane triangle with sides , since these satisfy the appropriate inequalities (unless
lie on the same geodesic, which case we exclude). The angles
of this plane triangle satisfy
by the boxed equality. In particular, if we let (resp.
) be the angles between the geodesics
(resp.
), then by symmetry and
This is a fact which I vaguely recall from popular-math books many years back. The rest is below the fold. (more…)