Let us consider a manifold and a hypersurface
. Given a smooth function
, we are interested in solving for
the eikonal equation
where the initial condition is for
smooth.
(The phrase “eikonal equation” seems to refer to a specific case of this, but I’ll follow Taylor in applying the term to this more general situation.)
Using the story already discussed about symplectic forms, we can do this locally in the noncharacteristic case.
To define this, we pick local coordinates around a fixed
such that
is given by
. Let the corresponding local coordinates for
be
together with
. Choose a cotangent vector
such that
. Suppose
, and
. This is the noncharacteristic hypothesis.
Theorem 1 Under the noncharacteristic hypothesis, the eikonal equation can be locally solved—that is, there exists a neighborhood
containing
and a smooth function
on
satisfying (*) with
. Moreover,
.
The idea of the proof of this existence theorem is to construct by constructing
, which in turn is done by constructing its graph—which after all must satisfy a specific equation—as a submanifold of
. At first it will not be obvious that the graph actually corresponds to any
. This will follow from the analysis of lagrangian submanifolds.
Lagrangian submanifolds of the cotangent bundle
Given a symplectic vector space (i.e. a vector space equipped with a nondegenerate skew-symmetric form
), a subspace
is said to be lagrangian if
and
. There is an easy example if we are given a symplectic basis
with
. Then the subspaces
spanned by the
(resp.
) are lagrangian.
A submanifold of a symplectic manifold
is lagrangian iff for
,
is a lagrangian subspace.
Proposition 2 Let
be a section (i.e. 1-form) embedding
as a submanifold of the cotangent bundle, which is endowed with the canonical form. Then
is lagrangian iff
is closed.
We will prove this by using local coordinates for
and corresponding
which together form a system of local coordinates on
. The symplectic form on
is then locally
Suppose in this local coordinates the map is defined by
or in other words
Then a basis for the tangent space of is given by
and we can compute
Comparing this with the local expression for shows that this is precisely the closedness condition.
Incidentally, I’m curious if there is an invariant proof here. Any ideas?
Constructing a surface in the cotangent bundle
We are now going to define the surface that will be the graph of , where
is the solution of the eikonal equation (*). We start with the fiber over
. Let
be the inclusion.
Define
In words, consists of cotangent vectors lying over
that annihilate
and which correspond to the differential of the boundary condition
plus possibly something extra in another direction. Near
,
is a surface of dimension
by the implicit function theorem and the noncharacteristic hypothesis. Take a neighborhood and intersect it with
to get
. So
is a surface over the intersection of
with some neighborhood of
then.
However, we need to extend this surface over a neighborhood of in
. We want
to be zero on this surface, and we know that
is constant on the integral curves of the Hamiltonian vector field
because
. So, we take the union of
with the integral curves of
through points of
. I now claim that this is a surface indeed. As before, choose local coordinates
about
and let
be the local coordinates for
. The symplectic form is locally given as
. Then because
,
includes a nonzero multiple of
. So this is indeed a surface of dimension
, which can be represented in some neighborhood of
as a section of
into
. And on this surface,
.
I claim now that the surface thus constructed is lagrangian, so we will be able to apply the previous result. So if
and
, we must prove then
.
We first do this when . If we actually have tangency to
, not simply
, i.e.
, then the fact that
follows from Proposition 2 with
replacing
that
, since the portion of the tangent vectors pointing orthogonally to
cancel each other out. (I.e. use local coordinates
so
is given by
; then the portions of
with
in them annihilate each other. The other parts, which consist of
for
, do so as well by what has already been proved.) Next, if one of
is a multiple of
at the point
, then
where denotes the application of the tangent vector
to
. If
are both multiples of
at
, then trivially
. So the symplectic form vanishes on
if
. The general case because the flows of the Hamiltonian vector field
preserve the symplectic form
, and every point on
is obtained by such a flow from
.
So, given the lagrangianness of the surface , we have thus found
with
satisfying the eikonal PDE above. Also,
, so by modifying
by a constant we get the appropriate boundary condition.
Next, I’ll try to say something about uniqueness, and more generally first-order nonlinear PDEs. After that, I’m thinking of possibly a post or two on integrable systems and perhaps the Arnold-Liouville theorem. Then perhaps some tools from analysis (e.g., distributions, Fourier transforms, Sobolev spaces, etc.) to get to the general theory of linear PDEs.
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